Question:
This code doesn't compile:
std::shared_ptr<MyType> pi = new MyType[5];
Instead, since the shared_ptr constructor is declared explicit , you have to write:
std::shared_ptr<MyType> pi(new MyType[5]);
I find it inconvenient to say the least.
What are the reasons for this design?
And what is the benefit from this?
Answer:
Let's say we have a function that accepts a smart pointer:
void foo(std::shared_ptr<Mytype> data){
//...
}
Then this code will lead to the removal of the resource, although we did not mean it:
MyType *object = new MyType();
foo(object);
When the function is called, a smart pointer will be created, and when it exits, it will delete the object it owned. And it will compile without any warnings.