Need help with C++

Question:

Why is the address displayed and not numbers?

here is an example:

#include <iostream>
using namespace std;
int main(void)
{
    int x,y;
    int numbers[10][10] = 
    {{1,2,3,2,7,1,8,1,6},
    {4,7,4,2,8,9,2,5,8},
    {4,9,3,3,6,2,8,4,2},
    {1,2,3,6,2,6,8,2,1}};

    for(x = 0;x < 10;x++){
        cout << *(numbers + x);
        for(y = 0;y < 10;y++){
            cout << *(numbers + y);
        }
    }

    return 0;
}

Answer:

• numbers is of type int [10][10]
• In this context, the type numbers is implicitly converted to type int (*)[10]
• The type numbers + i is also int (*)[10]
• Accordingly, the type *(numbers + i) is int [10]
• In this context, type int [10] is implicitly converted to type int *
• It is this int * that you output. That's why the address is displayed.

In other words, in your example, the address is displayed for the same reason that the address in

int a[10];
std::cout << a << std::endl;