Question:
I cannot open the graphic file. Tried this first:
#define FNAME "D:/Scream297and396.jpg"
...
int main() { char fname [50] =FNAME;
FILE *fout;
fout = fopen(FNAME,"r");
return 0; }
… but when you run this program nothing happens, the file does not open. More precisely, apparently, it still opens, but to read the file data itself with the same program.
I need to open the file not for the program , but for the user , in the default way in the operating system. In this case, the file D:/Scream297and396.jpg
should open in the image viewer set for *.jpg
.
How to do it?
Answer:
I suppose you want something like this:
ShellExecute(handle, "open", "D:\\Scream297and396.jpg", nullptr, nullptr, SW_SHOWNORMAL);
Read more about ShellExecute
capabilities on MSDN