Question: Question:
When the following sample.sh is run with bash, an error is thrown with a special variable to which a variable is assigned.
Probably because it is treated as a character string, I think that it is not pulling the argument, but is there any countermeasure?
[root@ test]# cat sample.sh
#!/bin/bash
echo $2
echo ${2}
N=2
echo ${$N}
[root@ test]# sh sample.sh a b c
b
b
sample.sh: 行 8: ${$N}: 誤った代入です
Answer:
#!/bin/bash
echo $2
echo ${2}
N=2
echo ${!N}
By
% ./sample.sh foo bar
bar
bar
bar
Can be realized.