Question:
In C ++ 11, there was such a possibility as:
enum AnyEnum : int8_t {
a = -1,
b = 0,
c = 1,
};
What type is set by default, ignoring the various optimizers? Earlier, if I am not mistaken, int;
set int;
…
Those. what will be delivered at compile time if the type is not specified?
Answer:
The documentation for std::underlying_type
states that:
The underlying type of an
enum
declared withenum class
isint
unless a different type is specified on declaration.
In translation:
The base type of an enumeration declared as an
enum class
isint
unless a different type is specified in the declaration.