python-3.x – Comparison between two objects in Python using the id() function with different result

Question:

In researching, I noticed that the id() function returns an integer and that it is guaranteed to be unique and constant for the object.

When comparing two objects with different results, what could have made these different results possible??

I noticed in a handout that the comparison id(Carro()) == id(Carro()) returns False but when executing the code it returned True

Car.py class

class Carro:
    pass

Code no Idle

>>> from Carro import Carro
>>> fusca = Carro()
>>> opala = Carro()
>>> id(opala) == id(fusca)
False
>>> id(Carro()) == id(Carro())
True

Answer:

In fact you didn't create two instances in:

>>> id(Carro()) == id(Carro())  # True

that's why True:

See the code below, it works on python2 or python3

>>> from carro import Carro
>>> fusca = Carro()
>>> opala = Carro()
>>> id(opala) == id(fusca)
False
>>> id(Carro()) == id(Carro())
True
>>> a = id(Carro()) 
>>> b = id(Carro())
>>> a
140356195163608
>>> b
140356195163720
>>> id(Carro())
140356195163608