python – Checking a list for emptiness

Question:

in my code the function

result = client.get_active_orders('ETH-BTC')['SELL']
print(result)

produces an empty list [] .

It can also display a non-empty list if there are active orders.

The question is: how, using if , to tell further code to be executed when the list is empty?

I try:

result = client.get_active_orders('ETH-BTC')['SELL']
if (result) == False:
    print(result)

using print I check to see if the code will be executed further. In my opinion "[]" should be printed. But nothing is printed. So my if block is wrong?

Answer:

An empty list cannot be false.

Try like this

if not result:
   print(True)