Algorithm for generating names

Question:

I did a lot of research but I couldn't find an algorithm that does something like banks do. For example, when you first register with a 24-hour teller, the machine will generate a password. Usually 3 or 4 pairs of letters are given as a password.

However, if noted, the letters they automatically generate make some sense if read as a word.

Example:

CE LA LU / XE GO U

Is it known something that accomplishes what I want?

Thanks!

Answer:

I made an algorithm of this in 2008. It ran in PHP.
I called it "pronounceable password"

The initial idea was like the @Motta comment.
Two lists: one for consonants and one for vowels:

ListaConsoantes = b c d f g j k l m n p r s t v x
ListaVogais = a e i o u

I improved the consonants and vowels to form more complex words:

ListaConsoantes  = b c d f g j k l m n p r s t v x 
ListaConsoantes2 = ch qu gu lh 
ListaConsoantesFim = s x r l m
ListaVogais      = a e i o u y 
ListaVogais2     = au ei oa ya

The function received the number of characters for the password to be generated, but this number was considered as a minimum so that the algorithm could complete the word, not stop in the middle of a syllable.

These phonemes can be enlarged and moved as you like.

the algorithm looked like this (in pseudocode):

size = 8
senha = ''
if ( rand entre 0 ou 1 )
    // inicio com uma vogal simples ou não da ListaVogais [1]
    senha = ListaVogais[ rand ]
while senha.size < size
     // sorteio se uso uma consoante de ListaConsoantes ou ListaConsoantes2 [2]
     if ( rand entre 0 ou 1 )
         senha = senha + ListaConsoantes[ rand ]
     else
         senha = senha + ListaConsoantes2[ rand ]

     // sorteio se uso uma vogal de ListaVogais ou ListaVogais2 [3]
     if ( rand entre 0 ou 1 )
         senha = senha + ListaVogais[ rand ]
     else
         senha = senha + ListaVogais2[ rand ]

     // sorteio se uso uma consoante no fim da palavra [4]
     if ( rand entre 0 ou 1 )
         senha = senha + ListaConsoantesFim[ rand ]

Come out, a pretty cool passwords.

could leave due to [1]:

baquichoba or baquichoba

could leave due to [2]:

baQUichoba or baDichoba

could leave due to [3]:

badOchoba or badAUchoba

could leave due to [4]:

banichoba or banichobaS

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